How many grams of copper oxide reacts with hydrogen if the result is 96 g of copper?

Copper oxide is reduced with hydrogen gas. This synthesizes metallic copper and water. This reaction is described by the following equation:

CuO + H2 = Cu + H2O;

Copper oxide reacts with hydrogen gas in equal molar amounts. In this case, equal (equivalent) amounts of copper and water are synthesized.

Let’s calculate the chemical amount of copper.

For this purpose, we divide the weight of the metal by the weight of 1 mole of metal.

M Cu = 64 grams / mol;

N Cu = 96/64 = 1.5 mol;

Thus, 1.5 mol of copper oxide can be reduced and 1.5 mol of copper can be synthesized.

The required weight of copper oxide is:

M CuO = 64 + 16 = 80 grams / mol;

m CuO = 1.5 x 80 = 120 grams;