How many grams of Cu (OH) 2 are formed in the reaction: 2NaOH + CuCl2 = 2NaCl + Cu (OH)

How many grams of Cu (OH) 2 are formed in the reaction: 2NaOH + CuCl2 = 2NaCl + Cu (OH) 2 if you took 102 grams of NaOH?

Given:
m (NaOH) = 102 g

To find:
m (Cu (OH) 2) -?

Decision:
1) 2NaOH + CuCl2 => 2NaCl + Cu (OH) 2;
2) M (NaOH) = Mr (NaOH) = Ar (Na) * N (Na) + Ar (O) * N (O) + Ar (H) * N (H) = 23 * 1 + 16 * 1 + 1 * 1 = 40 g / mol;
3) n (NaOH) = m (NaOH) / M (NaOH) = 102/40 = 2.6 mol;
4) n (Cu (OH) 2) = n (NaOH) / 2 = 2.6 / 2 = 1.3 mol;
5) M (Cu (OH) 2) = Mr (Cu (OH) 2) = Ar (Cu) * N (Cu) + Ar (O) * N (O) + Ar (H) * N (H) = 64 * 1 + 16 * 2 + 1 * 2 = 98 g / mol;
6) m (Cu (OH) 2) = n (Cu (OH) 2) * M (Cu (OH) 2) = 1.3 * 98 = 127 g.

Answer: The mass of Cu (OH) 2 is 127 g.