How many grams of cuso4 are there in 500 ml of 4m solution?

We make the proportion.
1 liter of solution – 4 mol
500 ml of solution – x mol.
X = 500 * 4: 1000 = 2 mol.
This means that the amount of copper sulfate substance is 2 mol.
Find the mass of copper sulfate, use the following formula.
n = m / M.
Where n is the amount of substance.
m is the mass of the substance.
M is the molar mass of the substance.
m = n * M.
M (CuSO4) = 64 + 32 + 16 * 4 = 160 g / mol.
m (CuSO4) = 160 g / mol * 2 mol = 320 g.
This means that the mass of copper sulfate is 320 grams.
Answer: m (CuSO4) = 320 g.