How many grams of ester can be obtained with a yield of 75% if 40 grams of 80% methanol solution and an excess

| December 8, 2020 | education

How many grams of ester can be obtained with a yield of 75% if 40 grams of 80% methanol solution and an excess of formic acid have entered into the reaction?

Given:
m (CH3OH) = 40 grams
w (CH3OH) = 80%
HCOOH w output (HCOOCH3) = 85%
find: m pr (HCOOCH3)
decision:
1) calculate the mass of methanol in an 80% solution weighing 40 grams:
m (CH3OH) = m solution?
w (solution) 100% = 40 grams?
80% \ 100% = 32 grams
2) calculate the theoretical mass of the ether:
32 grams x grams HCOOH + CH3OH = HCOOCH3 + H2O 32 grams 60 grams 32 grams – x grams 32 grams – 60 grams x = 32 grams? 60 grams \ 32 grams = 60 grams
find the practical mass of the product, taking into account its 75% yield:
m (pr) = m (theory)? w (output) \ 100% = m (pr) (HCOOCH3) = 60? 75% \ 100% = 45 grams
answer: m pr (HCOOCH3) = 45 grams.



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