How many grams of ethanol can be obtained from 112 liters of acetylene?

Let’s implement the solution:

In accordance with the condition of the problem, we write:
C2H2 + H2 = H2C = CH2 – hydrogenation, ethylene was formed;

H2 = CH2 + H2O = CH3 – CH2 – OH – hydration, ethanol was obtained.

M (C2H5OH) = 46 g / mol.

Let’s determine the amount of the original substance:
1 mole of gas at normal level – 22.4 liters;

X mol (C2H2) – 112 liters. hence, X mol (C2H2) = 1 * 112 / 22.4 = 5 mol.

Y (C2H4) = 5 mol.

Y (C2H5OH) = 5 mol, which is confirmed by the written equations.

Find the mass of the product:
m (C2H5OH) = Y * M = 5 * 46 = 230 g.

Answer: the mass of ethanol is 230 g.