How many grams of ethanol will hydrate 14 grams of ethylene?

Let’s execute the solution:

By the condition of the problem, we write down the process:
Н2С = СН2 + Н2О = С2Н5ОН – hydration, ethanol was obtained;

We make calculations:
M (C2H4) = 28 g / mol.

M (C2H5OH) = 46 g / mol.

Determine the amount of the original substance:
Y (C2H4) = m / M = 14/28 = 0.5 mol.

Y (C2H5OH) = 0.5 mol since the amount of substances according to the equation is 1 mol.

Let’s calculate the mass of alcohol:
m (C2H5OH) = Y * M = 0.5 * 46 = 23 g.

Answer: Ethanol with a mass of 23 g was obtained.