How many grams of ether is formed by the interaction of methyl alcohol with 10 g

How many grams of ether is formed by the interaction of methyl alcohol with 10 g of formic acid containing 1% of impurities?

Let’s execute the solution:

According to the condition of the problem, we write down the equation of the process:
НСООН + СН3ОН = НСОО – СН3 + Н2О – esterification, methyl formate is released;

We make calculations:
M (HCOOH) = 46 g / mol;

M (word ether) = 60 g / mol.

Determine the mass, the amount of acid:
m (HCOOH) = 10 * (1 – 0.10) = 9 g (mass without impurity);

Y (HCOOH) = m / M = 9/46 = 0.19 mol;

Y (ester) = 0.19 mol since the amount of substances is 1 mol.

4. Find the mass of the product:

m (sl. ether) = Y * M = 0.19 * 60 = 11.4 g

Answer: the mass of formic acid methyl ester is 11.4 g