How many grams of ethyl acetate will be obtained from 120 grams of acetic acid if the ester yield is 90%?

1. We make the equation:
CH3COOH + C2H5OH = CH3COO – C2H5 + H2O – esterification reaction, ethyl acetate was obtained;
2. Let’s calculate the molar masses of organic substances:
M (CH3COOH) = 60 g / mol;
M (ether) = 112 g / mol.
3. Determine the number of moles of the starting material:
Y (CH3COOH) = m / M = 120/60 = 2 mol;
Y (ether) = 2 mol since the amount of these substances according to the equation is 1 mol.
4. Find the theoretical mass of the ether:
m (ether) = Y * M = 2 * 112 = 224 g.
practical weight:
W = m (practical) / m (theoretical) * 100;
m (practical) = 0.90 * 224 = 201.6 g.
Answer: in the process of esterification, ethyl acetate with a mass of 201.6 g was obtained.