How many grams of ethyl alcohol is needed to produce 370g of diethyl ether?

Let’s execute the solution:
1. In accordance with the condition of the problem, we compose the equation:
C2H5OH + C2H5OH = C2H5 – O – C2H5 + H2O – esterification reaction, diethyl ether was formed;
2. Calculation of molar masses of organic substances:
M (C2H5OH) = 46 g / mol;
M (ether) = 74 g / mol.
3. Determine the number of moles of ether, if the mass is known:
Y (ether) = m / M = 270/74 = 3.65 mol;
Y (C2H5OH) = 3.65 mol since the amount of these substances according to the equation is equal to 1 mol.
4. Find the mass of ethanol:
m (C2H5OH) = Y * M = 3.65 * 46 = 167.9 g;
total weight: 167.9 * 2 = 335.8 g.
Answer: to obtain ether, ethyl alcohol weighing 335.8 g is required.