How many grams of formic aldehyde is formed by the interaction of 21 g of methyl alcohol with

How many grams of formic aldehyde is formed by the interaction of 21 g of methyl alcohol with the required amount of copper oxide.

By the condition of the problem, we write the equation:
CH3OH + CuO = HCOH + Cu + H2O – qualitative reaction to alcohol, formic aldehyde is formed;
Let’s make calculations using the formulas:
M (CH3OH) = 32 g / mol;
M (CH2O) = 30 g / mol;
Determine the amount of moles of methanol if the mass is known:
Y (CH3OH) = m / M = 21/32 = 0.66 mol;
Y (CH2O) = 0.66 mol, since according to the equation, the amount of mol of alcohol and aldehyde is 1 mol.
Find the mass of formic aldehyde:
m (CH2O) = Y * M = 0.66 * 30 = 19.8 g.
Answer: the mass of the aldehyde is 19.8 g.