How many grams of H2 will be obtained with 13 grams of zinc in a solution containing 35 grams of H2SO4?

Let’s execute the solution:

According to the condition of the problem, we compose the equation of the process:
Zn + H2SO4 = ZnSO4 + H2 – OBP, hydrogen is evolved;

Calculations:
M (Zn) = 65.3 g / mol;

M (H2) = 2 g / mol;

M (H2SO4) = 98 g / mol;

Y (Zn) = m / M = 13 / 65.3 = 0.2 mol (substance in excess);

Y (H2) = 0.2 mol since the amount of substances is 1 mol.

Y (H2SO4) = m / M = 35/98 = 0.4 mol (deficient substance).

Calculations are carried out taking into account the substance in deficiency.

Find the mass of the product:
m (H2) = Y * M = 0.4 * 2 = 0.8 g

Answer: the mass of hydrogen is 0.8 g



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