How many grams of HCl solution is required to dissolve 7.02 grams of zinc?

univerkov | March 8, 2021 | education

1.Let’s find the amount of substance Zn.

M (Zn) = 65 g / mol.

n = 7.02 g: 65 g / mol = 0.108 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

Zn + 2HCl = ZnCl2 + H2.

For 1 mol of Zn, there are 2 mol of HCl.

The substances are in quantitative ratios of 1: 2.

The amount of HCl substance is 2 times greater than the amount of Zn substance.

n (HCl) = 2n (Zn) = 0.108 × 2 = 0.216 mol.

3. Find the mass of HCl.

m = nM.

М (HCl) = 36.5 g / mol.

m = 0.216 mol × 36.5 g / mol = 7.88 g.

Answer: 7.3 g.

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