How many grams of hexachlorane is formed when benzene interacts with chlorine in the light from 150 g of benzene?

How many grams of hexachlorane is formed when benzene interacts with chlorine in the light from 150 g of benzene? Product yield 85%. Determine the number of moles of the formed hexachlorane.

Let’s implement the solution:

m = 150 g X g -? W = 85%

C6H6 + 3Cl2 = C6H6Cl6 – addition, hexachlorane was obtained;

Calculations according to the formulas of substances:
M (C6H6) = 78 g / mol;

M (C6H6Cl6) = 291 g / mol;

Y (C6H6) = m / M = 150/78 = 1.9 mol;

Y (C6H6Cl6) = 1.9 mol since the amount of these substances is 1 mol.

Find the mass of the product:
m (C6H6Cl6) = Y * M = 1.9 * 291 = 552.9 g (theoretical weight);

m (C6H6Cl6) = 0.85 * 552.9 = 469.96 g (practical weight).

Answer: the mass of hexachlorane was 469.96 g