How many grams of hydrochloric acid is required to form 5 g, in the reaction of hydrochloric acid with zinc.

If you have formed 5 g of salt, then:
Zn + 2Hcl = ZnCl2 + H2
n (ZnCl2) = 5/136 = 0.0368 mol
n (HCl) = 2n (ZnCl2) = 0.0735 mol
m (Hcl) = 0.0735 mol * 36.5 g / mol = 2.68 g

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