How many grams of hydrochloric acid should be taken to neutralize 116 g of magnesium hydroxide?

1. We make the equation:
X g -? m = 116 g;
2НCl + Mg (OH) 2 = MgCl2 + 2H2O – ion exchange reaction, magnesium chloride and water are released;
2. Calculation of the molar mass of inorganic substances:
M (HCl) = 36.6 g / mol;
M Mg (OH) 2 = 58.3 g / mol.
3. Determine the number of moles of magnesium hydroxide:
Y Mg (OH) 2 = m / M = 116 / 58.3 = 1.99 mol.
4. To calculate the amount of HCl mol, make up the proportion:
X mol (HCl) – 1.99 mol Mg (OH) 2;
-2 mol -1 mol hence, X mol (HCl) = 2 * 1.99 / 1 = 3.98 mol.
5. Find the mass of acid:
m (HCl) = Y * M = 3.98 * 36.6 = 145.67 g.
Answer: to carry out the reaction, hydrochloric acid weighing 145.67 g is required.