To solve this problem, we write down given: m (Zn) = 13 g. Zinc reacted with hydrochloric acid (HCl)
Find: the mass of the formed hydrogen.
To solve this problem, we write down the reaction equation for the interaction of zinc with hydrochloric acid.
Zn + HCl = ZnCl2 + H2
Let’s arrange the coefficients.
Zn + 2HCl = ZnCl2 + H2
Let’s calculate the molar masses of zinc and hydrogen.
M (Zn) = 65 g / mol
M (H2) = 1 * 2 = 2 g / mol
Over the zinc we write 13 g, and under the zinc – 65 g.
We write x g over hydrogen, and 2 g under hydrogen.
Let’s compose and solve the proportion:
x = 13 * 2/65 = 0.4 g
Answer: 0.4 g
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