How many grams of hydrogen will be released when 400 g of 27% hydrochloric acid solution reacts with aluminum?

Metallic aluminum interacts with hydrochloric acid. In this case, an aluminum chloride salt can be obtained and hydrogen gas bubbles are released. The reaction is described by the following equation.

Al + 3HCl = AlCl3 + 3/2 H2;

Let’s calculate the chemical amount of hydrochloric acid. To do this, divide its weight by the weight of 1 mole of acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 400 x 0.27 / 36.5 = 2.96 mol;

The chemical amount of released hydrogen will be 2 times less: 2.96 / 2 = 1.48 mol

Let’s define its volume.

For this purpose, we multiply the chemical amount of the substance by the volume of 1 mole of gas (filling the space with a volume of 22.4 liters).

V H2 = 1.48 x 22.4 = 33.14 liters;

The weight of hydrogen will be:

M H2 = 2 grams / mol;

m H2 = 2 x 1.48 = 2.96 grams;