How many grams of hydrogen will be released when potassium interacts with a solution of hydrogen

How many grams of hydrogen will be released when potassium interacts with a solution of hydrogen sulfide acid weighing 110 g?

Let’s implement the solution:

In accordance with the condition of the problem, we write down the equation of the process:
2K + H2S = K2S + H2 – OBP, hydrogen is evolved;

We make calculations using the formulas:
M (H2S) = 34 g / mol;

M (H2) = 2 g / mol.

Determine the amount of acid if the mass is known:
Y (H2S) = m / M = 110/34 = 3.2 mol;

Y (H2) = 3.2 mol since the amount of substances is 1 mol.

Find the mass of the product:
m (H2) = Y * M = 3.3 * 2 = 6.4 g

Answer: hydrogen was obtained with a mass of 6.4 g