How many grams of iodine will be obtained by the action of 16 g of bromine on a solution of potassium iodide?
| August 16, 2021 | education
The equation for the reaction of potassium iodide with bromine:
2KI + Br2 = 2KBr + I2
The amount of bromine substance:
v (Br2) = m (Br2) / M (Br2) = 16/160 = 0.1 (mol).
According to the reaction equation, 1 mol of I2 is formed per 1 mol of Br2, therefore:
v (I2) = v (Br2) = 0.1 (mol).
Thus, the mass of the iodine formed is:
m (I2) = v (I2) * M (I2) = 0.1 * 254 = 25.4 (g).
Answer: 25.4 g.
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