How many grams of iron can be obtained from 300 gr. ferric chloride.

We carry out the solution:
1. Let us write the equation according to the problem statement:
2FeCl3 + 3Zn = 2Fe + 3ZnCl2 – substitution reaction, released iron, zinc chloride;
2. We calculate the molar masses of substances:
M (FeCl3) = 162.3 g / mol;
M (Fe) = 55.8 g / mol.
3. Determine the number of moles of the starting material, if the mass is known:
Y (Zn) = m / M = 300 / 162.3 = 1.85 mol;
Y (Fe) = 1.85 mol since the amount of these substances according to the equation is 2 mol.
4. Calculate the mass of the reaction product:
m (Fe) = Y * M = 1.85 * 55.8 = 103.23 g.
Answer: during the reaction, iron was obtained with a mass of 103.23 g.