How many grams of iron did it react if 132g of iron (ll) sulfide was formed when it interacted with sulfur?

Given:
n (FeS) = 132g
n (Fe) -?
Decision:
Fe + S = feS
M (FeS) = 32 + 56 = 88 g \ mol
n (FeS) = 132 \ 88 = 1/5 mol
x = 132 * 1 \ 1.5 = 88 g
m (Fe) = 88
Answer: 88 grams



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