How many grams of iron (II) oxide will be obtained by oxidizing 24 mol of iron?

Let’s write the equation for the oxidation of iron to FeO:
2Fe + O2 = 2FeO
According to the equation, the amount of Fe is equal to the amount of FeO, which means that the reaction will result in 24 mol of FeO. Now let’s find the mass. m = nM. M (FeO) = 72g / mol. m (FeO) = 24 mol * 72 g / mol = 1728 g



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