How many grams of koh are there in 200 ml of a 10% solution with a density of 1.09 g / ml?

Given:
V solution (KOH) = 200 ml
ω (KOH) = 10%
ρ solution (KOH) = 1.09 g / ml

Find:
m (KOH) -?

Solution:
1) Calculate the mass of the potassium hydroxide solution:
m solution (KOH) = ρ solution (KOH) * V solution (KOH) = 1.09 * 200 = 218 g;
2) Calculate the mass of potassium hydroxide in solution:
m (KOH) = ω (KOH) * m solution (KOH) / 100% = 10% * 218/100% = 21.8 g.

Answer: The mass of potassium hydroxide is 21.8 g.