How many grams of limestone containing 95 percent calcium carbonate

How many grams of limestone containing 95 percent calcium carbonate (the rest is non-degradable impurities) were ignited if they received 56 liters of carbon dioxide.

The thermal decomposition reaction of calcium carbonate is described by the following chemical reaction equation:

CaCO3 = CaO + CO2 ↑;

Let’s calculate the chemical amount of carbon dioxide. To do this, we divide its volume by the volume of 1 mole of the substance.

N CO2 = 56 / 22.4 = 2.5 mol;

The same molar amount of calcium carbonate was decomposed.

Let’s calculate its weight taking into account the reaction yield of 95%:

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

m CaCO3 = 100 x 2.5 / 0.95 = 263.16 grams;