How many grams of limestone must be calcined so that 4.44 liters of 5% Ca (OH) 2 solution

How many grams of limestone must be calcined so that 4.44 liters of 5% Ca (OH) 2 solution can be obtained from the resulting quicklime?

To synthesize 1 mol of calcium hydroxide, it is necessary to decompose 1 mol of calcium carbonate. In this case, 1 mol of calcium oxide will be synthesized as an intermediate.

Let’s calculate the available chemical amount of calcium hydroxide substance.

To do this, divide the available weight of the oxide by the weight of one mole of hydroxide.

M Ca (OH) 2 = 40 + (16 + 1) x 2 = 74 grams / mol;

m Ca (OH) 2 = 4 440 x 0.05 = 222 grams;

N Ca (OH) 2 = 222/74 = 3 mol;

Let’s calculate the weight of the same amount of calcium carbonate.

To do this, multiply the amount of substance by the weight of 1 mole of calcium carbonate.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

m CaCO3 = 100 x 3 = 300 grams;