How many grams of magnesium oxide will be obtained by the interaction of magnesium weighing 4.8 g with oxygen.

Metallic magnesium reacts intensely with oxygen. The oxidation reaction is described by the following equation:

Mg + ½ O2 = MgO;

In this reaction, 1 oxygen atom is added to 1 magnesium atom and 1 molecule of magnesium oxide is synthesized.

Let’s determine the chemical amount of magnesium.

Divide the available weight of magnesium by the weight of 1 mole of this substance.

M Mg = 24 grams / mol; N Mg = 4.8 / 24 = 0.2 mol;

When this reaction proceeds, an equivalent amount of magnesium oxide will be synthesized.

Let’s determine its weight.

Let’s multiply the molar amount of the substance and the weight of 1 mole of the substance.

M MgO = 24 + 16 = 40 grams / mol; m MgO = 0.2 x 40 = 8 grams;