How many grams of matter is formed by the interaction of 240 g of sodium hydroxide

How many grams of matter is formed by the interaction of 240 g of sodium hydroxide with sulfuric acid, if the yield is 75% of the theoretical?

1) Let’s write the reaction equation:

2NaOH + H2SO4 = Na2SO4 + 2H2O

2) Find the theoretical mass of sodium sulfate:

n (NaOH) = m (NaOH) / Mr (NaOH) = 240/40 = 6 mol;

n (Na2SO4) theory = 0.5 * n (NaOH) = 0.5 * 6 = 3 mol;

m (Na2SO4) theory = n (Na2SO4) * Mr (Na2SO4) = 3 * 142 = 426 g;

3) Find the practical mass of sodium sulfate:

m (Na2SO4) practical = m (Na2SO4) theory * product yield = 426 * 0.75 = 319.5 g;

Answer: 319.5 g.