How many grams of mercury can be obtained from the decomposition of 43.4 mercury oxide (||)?

Decision:
1. Let’s write down the reaction equation:
2HgO = 2Hg + O2 – decomposition reaction, mercury and oxygen are released;
2. Let’s make calculations using the formulas:
M (HgO) = 200 + 16 = 216 g / mol;
M (Hg) = 200 g / mol;
3. Determine the amount of mol of mercury oxide, if the mass is known:
Y (HgO) = m / M = 43.4 / 216 = 0.2 mol;
4. Let’s make a proportion according to the reaction equation:
0.2 mol (HgO) – X mol (Hg);
-2 mol – 2 mol hence, X mol (Hg) = 0.2 * 2/2 = 0.2 mol;
5. Let’s calculate the mass of mercury by the formula:
M (Hg) = Y * M = 0.2 * 200 = 40 g.
Answer: in this reaction, 40 g of mercury is formed.