How many grams of mercury sulfide (cinnabar) will be obtained by mixing 32 g of serie and 100 g of mercury.

Let’s implement the solution:

In accordance with the condition of the problem, we write down the equation of the process:
Hg + S = HgS – compounds, mercury sulfide (cinnabar) was formed;

Calculations by formulas:
M (Hg) = 200.5 g / mol;

M (S) = 32 g / mol;

M (HgS) = 232.5 g / mol.

Let’s determine the amount of starting materials:
Y (Hg) = m / M = 100 / 200.5 = 0.5 mol (deficient substance);

Y (HgS) = 0.5 mol since the amount of substances is equal to 1 mol.

Y (S) = m / M = 32/32 = 1 mol (substance in excess).

Calculations are made for the substance in deficiency.

Find the mass of salt:
m (HgS) = Y * M = 0.5 * 232.5 = 116.25 g

Answer: obtained mercury sulfide weighing 116.25 g