How many grams of methane must be burned so that 100 liters are formed during combustion. carbon dioxide knowledge.

1. We make the equation:
CH4 + 2O2 = CO2 + 2H2O – the reaction of methane combustion is accompanied by the release of carbon dioxide and water;
2. Let’s define the molar masses of substances:
M (CH4) = 12 + 4 = 16 g / mol;

M (CO2) = 12 + 16 * 2 = 44 g / mol;
3. Let’s calculate the amount of CO2 moles, taking into account Avogadro’s law:
1 mol of gas at n. y – 22.4 l;
X mol (CO2) -100 L from here, X mol (CO2) = 1 * 100 / 22.4 = 4.46 mol;
4. Let’s make a proportion according to the reaction equation:
X mol (CH4) – 4.46 L;
-1 mol -1 mol hence, X mol (CH4) = 1 * 4.46 / 1 = 4.46 mol;
5. Determine the mass of methane by the formula:
m (CH4) = Y * M = 4.46 * 16 = 71.36 g.
Answer: for the combustion reaction, methane weighing 71.36 g is needed.