How many grams of Mg will react with 224 liters of oxygen.

univerkov | December 11, 2020 | education

Given:
V (O2) = 224 l.
Find: m (Mg) -?
Decision:
2Mg + O2 = 2MgO
n = V / Vm
n (O2) = 224 / 22.4 = 10 mol
Mg: O2 = 2: 1 (according to reaction level)
n (Mg) = n (O2) * 2 = 10 * 2 = 20
n = m / M
m = n * M
M (Mg) = 24 g / mol
m (Mg) = 24 * 10 = 480 g.
Answer: m (Mg) = 480 g.

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