To solve, we write down the equation of the process:
4Na + O2 = 2Na2O – compounds, sodium oxide obtained;
Calculations by formulas:
M (Na) = 22.9 g / mol;
M (Na2O) = 61.8 g / mol;
Y (Na) = m / M = 46 / 22.9 = 2 mol.
2 mol (Na) – X mol (Na2O);
-4 mol -2 mol from here, X mol (Na2O) = 2 * 2/4 = 1 mol.
Find the mass of the product:
m (Na2O) = Y * M = 1 * 61.8 = 61.8 g
Answer: the mass of sodium oxide is 61.8 g
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