How many grams of Na2O was formed if Na was oxidized 46 grams?

To solve, we write down the equation of the process:

4Na + O2 = 2Na2O – compounds, sodium oxide obtained;
Calculations by formulas:
M (Na) = 22.9 g / mol;

M (Na2O) = 61.8 g / mol;

Y (Na) = m / M = 46 / 22.9 = 2 mol.

Proportion:
2 mol (Na) – X mol (Na2O);

-4 mol -2 mol from here, X mol (Na2O) = 2 * 2/4 = 1 mol.

Find the mass of the product:
m (Na2O) = Y * M = 1 * 61.8 = 61.8 g

Answer: the mass of sodium oxide is 61.8 g