How many grams of NaCI with 15% moisture is required to prepare 1000 grams of a 10% solution?

Let us determine the masses of the components of the solution.

This requires multiplying their mass fraction by the weight of the solution.

Let’s calculate the weight of the dissolved salt.

M salt = 1000 x 0.1 = 100 grams;

It is necessary to hang 100 grams of dry salt.

Let’s find a sample of salt with a moisture content of 15%.

M salt 15% = 100 / 0.85 = 117.64 grams

In the same way, we find the weight of the solvent (water).

M water = 1000 x 0.9 = 900 grams;

Taking into account the water content in salt in the amount of 17.64 grams, it is necessary to hang 900 – 17.64 = 882.36 grams of water

Let’s check. To do this, add the masses of the components of the solution and get the weight of the solution in question.

100 + 17.64 + 882.36 = 1000;