How many grams of natural gas do you need to burn in order to heat the water in a 3kg kettle to 88 ° C?
| May 8, 2021 | education
Initial data: m1 (mass of heated water) = 3 kg; Δt (change in water temperature) = 88 ºС.
Constant data: according to the condition q (specific heat of combustion of natural gas) = 44 MJ / kg or 44 * 10 ^ 6 J / kg; C (specific heat of water) = 4200 J / (kg * K).
Since heat losses can be neglected, we calculate the mass of natural gas from the ratio: C * m1 * Δt = q * m2.
m2 = C * m1 * Δt / q = 4200 * 3 * 88 / (44 * 10 ^ 6) = 0.0252 kg or 25.2 g.
Answer: You need to burn 25.2 grams of natural gas.
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