How many grams of nitric acid can react with 20 grams of aluminum hydroxide?

univerkov | January 17, 2021 | education

Given:
m (Al (OH) 3) = 20 g
To find:
m (HNO3)
Decision:
Al (OH) 3 + 3HNO3 = Al (NO3) 3 + 3H2O
n (Al (OH) 3) = m / M = 20 g / 78 g / mol = 0.256 mol
n (Al (OH) 3): n (HNO3) = 1: 3
n (HNO3) = 0.256 mol * 3 = 0.768 mol
m (HNO3) = n * M = 0.768 mol * 63 g / mol = 48 g
Answer: 48 g

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