How many grams of nitric acid can react with a solution containing 38.7 g of aluminum hydroxide?

univerkov | February 1, 2021 | education

Reaction equation: 3HNO3 + Al (OH) 3 = Al (NO3) 3 + 3H2O
Find the amount of aluminum hydroxide substance: n = m / M = 38.7 g / 78 g / mol = 0.5 mol. (M – molar mass, determined by the periodic table).
By reaction with 3 mol of nitric acid, 1 mol of aluminum hydroxide reacts, n (HNO3) / 3 = 0.5 / 1. n (HNO3) = 3 * 0.5 / 1 = 1.5 mol. Find the mass of nitric acid m = n * M = 1.5 mol * 63 g / mol = 94.5 g.
Answer: the mass of nitric acid is 94.5 g.

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