How many grams of nitrogen can be obtained by decomposing 192 g of ammonium nitrite?

For the solution, let’s write down the data:

m = 192 g X g -?

NH4NO2 = N2 + 2H2O – decomposition, nitrogen obtained.

We make calculations:
M (NH4NO3) = 64 g / mol;

M (N2) = 28 g / mol;

Y (NH4NO2) = m / M = 192/64 = 3 mol;

Y (N2) = 3 mol since the amount of substances is 1 mol.

3. Find the mass of the product:

m (N2) = Y * M = 3 * 28 = 84 g

Answer: The mass of nitrogen is 84 g