How many grams of oxide is formed by the decomposition of 49 g, copper hydroxide (||)?

univerkov | August 2, 2021 | education

Let us write the reaction equation for the decomposition of copper hydroxide:

Cu (OH) 2 = CuO + H2O.

Let’s calculate the number of moles of substances, since for all it will be the same.

n (Cu (OH) 2) = m • Mr = 49/98 = 0.5 mol.

n (Cu (OH) 2) = n (CuO).

The mass of the oxide is.

m (CuO) = n • Mr = 0.5 • 80 = 40 g.

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