How many grams of oxygen do you need to take to get 71 grams of phosphorus oxide?

The synthesis reaction of phosphorus oxide is described by the following chemical reaction equation:

4P + 5O2 = 2P2O5;

4 phosphorus atoms interact with 5 oxygen molecules. In this case, 2 molecules of phosphorus oxide are synthesized.

Let’s calculate the chemical amount of a substance in phosphorus oxide weighing 71 grams.

M P2O5 = 31 x 2 + 16 x 5 = 142 grams / mol;

N P2O5 = 71/142 = 0.5 mol;

For the synthesis of such an amount of oxide, 0.5 x 5/2 = 1.25 mol of oxygen will be required.

The oxygen weight will be:

M O2 = 16 x 2 = 32 grams / mol;

m O2 = 1.25 x 32 = 40 grams;