How many grams of oxygen is needed to completely oxidize 540 grams of glucose?

How many grams of oxygen is needed to completely oxidize 540 grams of glucose? What is the maximum amount of ATP (in moles) that can be synthesized in the body?

Glucose in the cell undergoes glycolysis, where 2 mol of ATP is synthesized per 1 mol, and then it is oxidized, forming another 36 mol of ATP. We use the total dissimilation equation.
C6H12O6 + 6O2 + 38ADP + 38H3PO4 = 6CO2 + 38ATF + 44H2O
1) Мr (С6Н12О6) = 180, and Мr (О2) = 32.
for the oxidation of 540 g of С6Н12О6, x g of О2 is needed, and for 180 g – 192 g (since 6 mol of О2). Hence, 540/180 = x / 192,
x = 540 * 192/180 = 576g
2) From 540 g of С6Н12О6 we get x mol of ATP, and from 180g – 38 mol, which means 540/180 = x / 38,
x = 540 * 38/180 = 114 mol.