How many grams of oxygen react with 130 grams of zinc?

Zinc is oxidized by oxygen. The reaction is described by the following equation.

Zn + ½ O2 = ZnO;

1 mol of metallic zinc reacts with 0.5 mol of oxygen. This synthesizes 1 mole of zinc oxide.

Let’s determine the chemical amount of a substance contained in 180 grams of zinc.

M Zn = 65 grams / mol;

N Zn = 130/65 = 2 mol;

To burn this amount of zinc, you need 2/2 = 1 mole of oxygen.

Let’s calculate its mass.

To do this, multiply the amount of substance by the weight of 1 mole of gas.

M O2 = 16 x 2 = 32 grams / mol;

m O2 = 1 x 32 = 32 grams;