How many grams of phosphorus can react with 4.48 liters of oxygen?

The synthesis reaction of phosphorus oxide is described by the following chemical reaction equation:

4P + 5O2 = 2P2O5;

4 phosphorus atoms interact with 5 oxygen molecules. In this case, 2 molecules of phosphorus oxide are synthesized.

Let’s calculate the chemical amount of a substance in 4.48 liters of oxygen.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

N O2 = 4.48 / 22.4 = 0.2 mol;

With this amount of oxygen, 0.2 / 5 x 4 = 0.16 mol of phosphorus will react.

Let’s calculate its weight.

To do this, we multiply the amount of the substance by its molar weight.

M P = 31 grams / mol;

m P = 31 x 0.16 = 4.96 grams;