How many grams of potassium carbonate will be required to prepare 200 ml of 0.3 m solution?

Let’s find the required amount of the substance for the preparation of this solution.

To do this, multiply the volume of the solution and its molar concentration.

In order to prepare such a solution, it is necessary to weigh and dissolve 0.3 x 0.2 = 0.06 mol of salt in water.

Let’s calculate the required weight of salt.

To do this, we find the product of the molar weight of the salt and the amount of substance.

M KCO3 = 39 + 12 + 16 x 3 = 99 grams / mol;

m KCO3 = 0.06 x 99 = 5.94 grams;