How many grams of precipitate is formed as a result of the interaction of sodium hydroxide and 10 grams of copper II sulfate?

CuSO4 + 2NaOH = NaSO4 + Cu (OH) 2 sediment
Let’s find the amount of a substance by the formula n = m / M, where n is the amount of a substance, m is the mass of a substance, M is the molar mass of a substance
M (CuSO4) = 160 g / mol
n (CuSO4) = 10/160 = 0.0625 mol
n (CuSO4) = n (Cu (OH) 2)
Find the mass of the sediment by the formula m = M × n
M (Cu (OH) 2) = 98 g / mol
m (Cu (OH) 2) = 98 × 0.0625 = 6.125 g
Answer: sediment mass = 6.125 g