How many grams of precipitate is formed when hydrochloric acid acts on a solution of Argentum

How many grams of precipitate is formed when hydrochloric acid acts on a solution of Argentum nitrate, which contains 1.7 g of salt?

Given:
m (AgNO3) = 1.7 g

To find:
m (draft) -?

1) HCl + AgNO3 => AgCl ↓ + HNO3;
2) n (AgNO3) = m / M = 1.7 / 170 = 0.01 mol;
3) n (AgCl) = n (AgNO3) = 0.01 mol;
4) m (AgCl) = n * M = 0.01 * 143.5 = 1.435 g.

Answer: The mass of AgCl is 1.435 g.