How many grams of salt and how much water is needed to prepare 80 g of a 10% solution?

First, you need to determine the mass of the salt.

m salt = 80 * 0.1 = 8 g.

This means that the mass of salt is 8 g.

Next, you need to determine the mass of water in this solution.

80 – 8 = 72 g.

This means that the mass of water is 72 g.

Let’s determine the volume of water.

M (H2O) = 1 * 2 + 16 = 18 g / mol.

m / M = V / Vm.

Where m is mass.

M – paint mass.

V is the volume.

Vm is the molar volume.

V = m * Vm / M.

V = 22.4 * 72/18 = 89.6 liters.

This means that the volume of water is 89.6 liters.

Answer: the volume of water is 86.6 liters.