1. We compose the reaction equation:
2 NaOH + H2SO4 = Na2SO4 + 2 H2O
According to the equation: 2 mol of NaOH enters the reaction. We find its mass:
m (NaOH) = n * M = 2 mol * (23 + 1 + 16) = 80 g
According to the equation: 1 mol of salt was formed. We find its mass:
m (Na2SO4) = n * M = 1 mol * (23 * 2 + 32 + 16 * 4) = 142 g
2. Let’s calculate the mass of salt, making up the proportion:
20 g NaOH – x g Na2SO4
80 g NaOH – 142 g Na2SO4
Hence, x = 20 * 142/80 = 35.5 g.
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