How many grams of salt will be obtained by reacting 20 g of sodium hydroxide with sulfuric acid?

1. We compose the reaction equation:

2 NaOH + H2SO4 = Na2SO4 + 2 H2O

According to the equation: 2 mol of NaOH enters the reaction. We find its mass:

m (NaOH) = n * M = 2 mol * (23 + 1 + 16) = 80 g

According to the equation: 1 mol of salt was formed. We find its mass:

m (Na2SO4) = n * M = 1 mol * (23 * 2 + 32 + 16 * 4) = 142 g

2. Let’s calculate the mass of salt, making up the proportion:

20 g NaOH – x g Na2SO4

80 g NaOH – 142 g Na2SO4

Hence, x = 20 * 142/80 = 35.5 g.