How many grams of silicic acid can be obtained from 41.8 g of technical potassium silicate containing 8% impurities?

To solve the problem, let’s write down the data:

K2SiO3 + 2HCl = H2SiO3 + 2KCl – ion exchange, silicic acid is released;

Calculations:
M (K2SiO3) = 154.2 g / mol;

M (H2SiO3) = 78 g / mol;

m (K2SiO3) = 41.8 * (1 – 0.8) = 8.36 g (mass without impurity);

Y (K2SiO3) = m / M = 8.36 / 154.2 = 0.05 mol;

Y (H2SiO3) = 0.05 mol since the amount of substances is 1 mol.

3. Find the mass of the product:

m (H2SiO3) = Y * M = 0.05 * 78 = 3.9 g

Answer: the mass of silicic acid is 3.9 g