How many grams of silicic acid is formed by the reaction of sodium silicate with 250 ml of 20%

| April 1, 2021 | education

How many grams of silicic acid is formed by the reaction of sodium silicate with 250 ml of 20% hydrochloric acid solution (density 1.1 g / ml).

1. Let’s find the mass of the HCl solution by the formula:

m = p * V = 1.1 g / ml * 250 ml = 275 g solution

2. Let’s calculate the mass of НСl in solution according to the formula:

m (p. in-va) = m (solution) * w (solution) / 100% = 275 * 20/100 = 55 g HCl

3. Let’s compose the reaction equation:

Na2SiO3 + 2 НСl = Н2SiO3 + 2 NaCl

According to the equation: НСl – 2 mol, and Н2SiO3 – 1 mol. We find their masses:

m (HCl) = n * M = 2 mol * (1 + 35.5) = 73 g

m (H2SiO3) = n * M = 1 mol * (1 * 2 + 28 + 16 * 3) = 78 g

4. Let’s calculate the mass of Н2SiO3, making up the proportion:

55 g HCl – x g H2SiO3

73 g HCl – 78 g H2SiO3

Hence, x = 55 * 78/73 = 58.8 g.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.