How many grams of sodium acetane can be obtained by reacting 30 acetic acid
How many grams of sodium acetane can be obtained by reacting 30 acetic acid with sodium hydroken, if the practical product yield is 60%.
1. According to the condition of the problem, we compose the equation:
CH3COOH + NaOH = CH3COONa + H2O – exchange process, sodium acetate was obtained;
2. Let’s make the calculations:
M (CH3COOH) = 60 g / mol;
M (CH3COONa) = 78.98 g / mol.
3. Determine the amount of mol of acetic acid, if the mass is known:
Y (CH3COOH) = m / M = 30/60 = 0.5 mol;
Y (CH3COONa) = 0.5 mol since the amount of these substances according to the equation is 1 mol.
4. Find the theoretical mass of salt – CH3COONa:
m (CH3COONa) = Y * M = 0.5 * 78.98 = 39.49 g.
We calculate the practical weight by the formula:
W = m (practical) * m (theoretical) * 100;
m (practical) = 0.60 * 39.49 = 23.69 g.
Answer: the mass of the organic sodium acetate salt is 23.69 g.